00:01
All right, two things we have to do here.
00:02
We have to come up with a formula for the nth term.
00:07
And these have to be in terms of fibonacci numbers.
00:11
So f of something, where f is a fibonacci term.
00:15
Then we have to prove it works for all real numbers.
00:18
So let's go ahead and just start plugging some numbers in.
00:22
So if i plug in one for n, that means, oh, also we are given that the first term.
00:30
Is one.
00:32
Okay, so now when i plug in one for n, i get one plus one.
00:36
We're finding the second term.
00:38
So i might as well finish this off and say is one over one plus the first term.
00:47
Well, we know the first term.
00:49
The first term is one.
00:51
So this is one plus one over one, one over two, one half.
00:56
Okay, let's do the next one.
00:59
That would be plugging in a two for n, which really means we're actually finding the third term.
01:04
It's kind of how it works when you're plugging in a two.
01:06
You're not finding the second term.
01:07
Anyway, one plus one plus.
01:11
And remember, this is a to the n, and we're saying n is two.
01:17
And i'm going to go ahead and say a to the two, that's this one half here.
01:22
So let's go ahead and plug that in right now.
01:24
One half.
01:27
And i'll go ahead and do a couple steps.
01:28
This one's a little bit more complex one over well one plus a half is one and a half or three over two and if you're dividing by a fraction that's the same thing is multiplying one times the reciprocal of this slip numerator and denominator two over three well that's two thirds hopefully you're starting to see the pattern i'll do one more and then i'll just write in a couple of the next terms but i think it doesn't really really stand out maybe until we do one more so we get, this is going to be a three or the third term.
02:07
There is that third term.
02:08
So i'm going to go ahead and plug into two thirds.
02:13
All right.
02:13
That becomes one over one plus two thirds is five thirds.
02:19
And remember, that's the same thing as saying multiply one, the numerator, by the reciprocal, three -fits.
02:27
And so i'm going to line these up...