00:01
In drosophila, scientists were interested in understanding how these four homozygous mutation lines were behaving.
00:09
And so we were provided some data in the form of a table where each of the four strains were bred with each other to see what happens to the mutant phenotype.
00:23
And so what we saw was that some strains when bred to other strains produced a wild type phenotype.
00:31
Which is indicated by the plus.
00:36
So that means normal walking.
00:39
And other strains are indicated by a minus, and that is erratic walking.
00:46
The first thing that jumps out to me in this table is that this set of minuses here.
00:52
So the erratic walking is found still when strain two is spread to strain three, you still get a mutant phenotype.
01:02
And the same thing is true when strain three, obviously is bred to strain two, you get a mutant phenotype.
01:07
This tells me that these are alleles of the same gene, and that what we're looking at is a complementation test.
01:23
And remember, a complementation test is used to identify the number of genes that can mutate to a specific phenotype.
01:33
And so if offspring of a given cross, and we can use these two here as our examples, two by three and three by two, express the mutant phenotype, then what we're saying is the mutations found in one strain do not complement the mutations found in the second strain.
01:51
And so you still yield a mutant phenotype.
01:55
However, if you have progeny such as that's found here, say a one by four cross, you yield a wild type phenotype from a mutated one strain crossed with a mutated four strain, that tells me that the mutations in one complement the mutations found in four, and that those mutations together yield a wild type phenotype.
02:21
So they're carrying mutant alleles of separate genes.
02:25
And so we can determine, based on this table, that there are three genes involved in this cross.
02:33
And so i'm going to scoot this up at any bit, and then we can identify the different, genes and alleles.
02:41
So if we have say a and little a, that'll represent gene one, b and little b, and that will represent gene two.
02:50
And i'm going to use d because cs are terrible to tell capital from lowercase, and that's going to represent gene three.
03:00
And i'm going to use, there must be two forms of mutated d.
03:06
So i'm going to use one and two or two and three.
03:10
Okay, so let's look at our cross.
03:13
If we cross strain one with strain two, that has to be a phenotype, our genotype, big a, little a, big b, big b, big d, little d.
03:25
And that tells us that we're going to get a wild type because we have at least one dominant allele from this cross of one to two.
03:35
And then these recessive alleles are found in different strains.
03:40
If we do cross 1 by 3, it's going to be big a, little a, big b, big b, big b, big b, little d.
03:48
And it must be a 3 because you get a wild phenotype that's there.
03:53
And then 1 by 4, it's going to be big a, little a, heterozygous b, and homozygous dominant for d.
04:01
And that yields a wild type...