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Fourier sine transform of $f^{\prime}(x)$ in the interval $(0, D)$ is .......
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The Fourier sine transform of a function \( f(x) \) defined on the interval \( (0, D) \) is given by: \[ F_s(f) = \int_0^D f(x) \sin\left(\frac{n\pi x}{D}\right) \, dx \] where \( n \) is a positive integer. Show more…
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