00:01
So for this equation, i'm asked to solve this equation using bernoulli's equations.
00:07
So my first step here is to divide out whatever this y -tip power is.
00:12
So when i divide that out across everything, i get y -squared, k -y -d -x plus y -cute, is equal to use the x.
00:24
And then now, like, past problems, i'm going to go ahead and make a substitution here.
00:28
So my substitution is always just going to be whatever is right here.
00:32
So it's going to be y -cubed.
00:35
So differentiating on both sides, i get d -u -d -x is equal to 3y -squared, d -y -d -x.
00:45
And my goal here is to replace this term with my d -u -d -x.
00:49
So all i need to do is just divide out that three.
00:53
So i have one -third d -u -d -x.
00:56
It's equal to y -squared, d -y -d -x.
01:00
So now i'm going to replace my first.
01:03
Term here with its equivalence.
01:06
And when i do that, i get one -third d -u -d -x plus a u because u is my y -q2.
01:18
It's equal to e to the x.
01:20
And so then from here i'm going to solve this using integrating factor.
01:24
But before i do that, this has to be in standard forms...