Question
$$\frac{x^{2}}{y}+\frac{y^{2}}{x}=18, x+y=12$$
Step 1
Step 1: First, we rewrite the first equation as follows: $$ x^{3}+y^{3}=18xy $$ This can be done by multiplying each term by $x$ or $y$ respectively. Show more…
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$$y^{\prime \prime \prime}+2 y^{\prime \prime}-9 y^{\prime}-18 y=-18 x^{2}-18 x+22$$; $$y(0)=-2, \quad y^{\prime}(0)=-8, \quad y^{\prime \prime}(0)=-12$$
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