00:01
Okay, so here we have the non -homogeneous equation, the third derivative of z plus three times the second derivative minus four times z is equal to e to the 2x.
00:21
So let's take a look at the corresponding auxiliary equation, which would be r cubed plus 3r squared minus 4.
00:33
We set that equal to 0, and we get r is equal to 1, negative 2, and negative 2.
00:56
I guess that means our homogeneous solution is going to be some constant times e to the power of x plus c2 times e to the negative 2x plus c2 times e to the negative 2x plus c3 times x times e to the negative 2x.
01:28
And this x here is due to the multiplicity of the negative 2.
01:35
So this means our fundamental solution set is going to be e to the power of x, e to the negative 2x, and x times e to the negative 2x.
01:53
So we want a particular solution.
02:13
So the particular solution will be of the form, some constant times e to the x plus v2, e to the negative 2x, plus v3e to the negative 2x times x, where v1, v2, and v3, and v3 are all functions of x.
02:51
So to determine those, we take our matrix where the first row is each of the functions from our function set.
03:09
The second row is the derivative, first derivative of them.
03:24
So negative 2x, e to the negative 2x plus e to the negative 2x.
03:32
And then the third row is going to be the second derivative on that first one.
03:37
The first column is nice and easy.
03:44
And the last one here is 4xe to the negative 2x, minus 4e to the negative 2x.
04:00
Okay, so we want to find the determinant of that, and when we do, we will get 9e to the negative 3x.
04:21
And then we also want to get our sub -determinants here.
04:38
So if this is w, so we would consider w1 would be negative 1 squared times.
05:09
So we're considering the functions e to the negative 2x and xe to the negative 2x.
05:26
So we're just taking the first derivatives.
05:40
Of course you have them above.
05:41
So there's no like calculations here, just some copying.
05:47
Okay, but when we calculate this determinant, we end up with e to the negative 4x...