00:01
Question 64 asks, a rock release from rest to fall in a small airless planet falls y equals gt squared meters in t seconds and g is a constant.
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And it reaches 20 meters below in t equals four seconds.
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So part a has to find the g value.
00:18
And this can really be simply done by substituting what we know.
00:22
So what we're given is y equals gt squared.
00:26
We know that at t equals four seconds, and i'm going to put this in red, at 4 seconds, we are at 20 meters.
00:38
Therefore, this is 4 times 4 is 16.
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16.
00:44
I'm going to write up here.
00:46
20 divided by 16 is equal to g.
00:49
And when we simplify, we are going to get 5 over 4 as our g constant right here.
01:00
Part b asks to find the average speed for the fall.
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And we did this in an earlier problem, but we're going to do it again.
01:08
And again, to find the average b, we are going to do change of y over change of t.
01:14
And we know that we want to find the y at four seconds.
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Therefore, we are going to take the formula that we do know, which is y is equal to 5 over 4 t squared.
01:30
And this time we do know g.
01:32
So we are going to substitute g as 5 over 4, which is just equal to 1 .25.
01:39
And going back up here, we have 1 minus 1 .25.
01:43
And the other time that we do know, and the height that we do know at the time is 0 seconds.
01:53
So on the bottom is a change of time, which is just 4 minus 0.
01:58
And when you put this into the calculator, you're going to get 20 in numerator, divide by 4 in the denominator.
02:06
Therefore, the average speed for the fall is 5 meters per second.
02:12
Oh, sorry.
02:14
I wrote feet for some reason...