From a point at a height $h$ above the oround, a particle $A$ is projected with a velocity $v$ in an upward direction making an angle $\theta$ with the horizontal. $\Lambda$ nother particle $B$ is projected from the same point with the same velocity $v$ but, in a direction directly opposite to $A$. Show that the two particles hit the ground al a distanec $\frac{2 v}{g} \cos \theta \sqrt{\left(v^{2} \sin ^{2} \theta+2 g h\right)}$ apart.