[From Adkins] Below $100 \mathrm{~K}$ the specific heat capacity of diamond varies as the cube of temperature: $c_p=a T^3$. A small diamond of mass $100 \mathrm{mg}$ is cooled to $77 \mathrm{~K}$ by immersion in liquid nitrogen, and then dropped into a bath of liquid helium at its boiling point of $4.2 \mathrm{~K}$ at atmospheric pressure. In cooling the diamond, some of the helium is boiled off. The gas is collected and found to occupy a volume $2.48 \times 10^{-5} \mathrm{~m}^3$ at $0^{\circ} \mathrm{C}$ and 1 atmosphere pressure. What is the value of $a$ in the formula for the specific heat capacity of diamond? [The latent heat of vaporization of helium at $1 \mathrm{~atm}$ is $21 \mathrm{~kJ} / \mathrm{kg}$.]