00:01
For all the calculations in this problem, we're going to use the standard state, delta g of formation, delta h of formation, and then the absolute entropy value for all reactants and products that are found in these chemical reactions.
00:20
What we do is we look up the values i just discussed, standard delta g's of formation, delta h is of formation, and absolute standard entropyes.
00:29
And we take those values for the products multiplied by their coefficients and subtract off those values for the reactants multiplied by their coefficients.
00:46
And this is how we determine the change in entropy, enthalpy, and gives free energy for the entire reactions.
00:56
For the first chemical reaction, this one here, we will look up the delta h, delta g, and s values for carbon dioxide first, multiplied by its coefficient of 1.
01:15
Delta h of formation for carbon dioxide is negative 393 .5, delta g of formation is negative 394, and absolute s is 214.
01:25
We'll then do it for water, two times the delta h of formation of water.
01:30
In standard state, 242, and then delta g, and then s, and then we'll subtract off 1 times the delta h of formation of methane gas, negative 75, delta g of formation of methane gas, negative 51, and entropy of methane gas 186.
01:51
And then last of all, for oxygen, 2 times, delta h of formation, which is 0, delta g of formation is zero for oxygen and entropy is 205 and then we sum everything up so the delta h standard for this entire reaction is negative 202 .5 kilojoules delta g standard for this reaction is negative 801 kilojoules and delta s standard for this reaction is negative 4 joules per kelvin remember all these values in the back of the book are in kilojoules for delta h and delta g, but they're in units of joules per kelvin for s.
02:38
Now we'll move on to the next reaction.
02:41
6 moles carbon dioxide reacts with 6 moles liquid water, producing 1 mole of glucose, and 6 moles of oxygen.
02:53
Again, we'll go to the back of the book.
02:57
1 mole, multiplied by the delta h of formation of glucose, negative 127, delta g of formation of glucose, negative 1 .27, delta g of formation of glucose, negative 9, 11 and 1 times the absolute s of glucose as a solid 212 joules per kelvin.
03:14
We'll then do the same thing for oxygen and then subtract off six times the delta h of formation of carbon dioxide negative 393 .5, 6 times the delta g of formation of carbon dioxide negative 394 and then six times the entropy of carbon dioxide 214 jules per kelvin.
03:35
And then last of all for liquid water.
03:39
6 times the delta h of formation, 6 times the delta g of formation, and 6 times the entropy...