Question
From experiment, we know that $\left[\mathrm{CoF}_{6}\right]^{3-}$ is paramagnetic and $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ is diamagnetic. Using the ligand field model, depict the electron configuration for each ion, and use this model to explain the magnetic property. What can you conclude about the effect of these ligands on the magnitude of $\Delta_{0} ?$
Step 1
In $\left[\mathrm{CoF}_{6}\right]^{3-}$, the six fluorine atoms each contribute a charge of -1, resulting in a total charge of -6. To achieve the overall charge of -3, the cobalt must have an oxidation state of +3. Similarly, in Show more…
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From experiment we know that $\left[\mathrm{CoF}_{6}\right]^{3-}$ is para magnetic and $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ is diamagnetic. Using the ligand field model, depict the electron configuration for each ion and use this model to explain the magnetic property. What can you conclude about the effect of the ligand on the magnitude of $\Delta_{0} ?$
The complex $\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ has five unpaired electrons, whereas $\left[\mathrm{Mn}(\mathrm{CN})_{6}\right]^{4-}$ has only one. Using the ligand field model, depict the electron configuration for each ion. What can you conclude about the effects of the different ligands on the magnitude of $\Delta_{0} ?$
The complex $\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ has five unpaired electrons, whereas $\left[\mathrm{Mn}(\mathrm{CN})_{6}\right]^{4-}$ has only one. Using the ligand field model, depict the electron configuration for each ion. What can you conclude about the effects of the different ligands on the magnitude of $\Delta ?$
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