Problem

Use the following equations to answer the next fo…

01:41

Problem 11 Easy Difficulty

From the balanced molecular equations, write the complete ionic and net ionic equations for the following:
(a) $\mathrm{K}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(a q)+\mathrm{Ba(OH} )_{2}(a q) \longrightarrow 2 \mathrm{KOH}(a q)+\mathrm{BaC}_{2} \mathrm{O}_{4}(s)$
(b) $\operatorname{Pb}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{PbSO}_{4}(s)+2 \mathrm{HNO}_{3}(a q)$
(c) $\mathrm{CaCO}_{3}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow \mathrm{CaSO}_{4}(s)+\mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)$

Answer

(a)
Complete Ionic
$2 \mathrm{K}^{+}(a q)+\mathrm{C}_{2} \mathrm{O}_{4}^{2-}(a q)+\mathrm{Ba}^{2+}(a q)+2 \mathrm{OH}^{-}(a q) \longrightarrow 2 \mathrm{K}^{+}(a q)+2 \mathrm{OH}^{-}(a q)+\mathrm{B}$
Net Ionic
$\mathrm{C}_{2} \mathrm{O}_{4}^{2-}(a q)+\mathrm{Ba}^{2+}(a q) \longrightarrow \mathrm{BaC}_{2} \mathrm{O}_{4}(s)$
(b)
Complete Ionic
$\mathrm{Pb}^{2+}(a q)+2 \mathrm{NO}_{3}^{2-}(a q)+2 \mathrm{H}^{+}(a q)+\mathrm{SO}_{4}^{2-}(a q) \longrightarrow \mathrm{PbSO}_{4}(s)+2 \mathrm{H}^{+}(a q)+2 \mathrm{NO}_{3}^{-}$
Net Ionic
$\mathrm{Pb}^{2+}(a q)+\mathrm{SO}_{4}^{2-}(a q) \longrightarrow \mathrm{PbSO}_{4}(s)$
(c)
Complete Ionic
$\mathrm{CaCO}_{3}(s)+2 \mathrm{H}^{+}(a q)+\mathrm{SO}_{4}^{2-}(a q) \longrightarrow \mathrm{CaSO}_{4}(s)+\mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)$
Net Ionic
$\mathrm{CaCO}_{3}(s)+2 \mathrm{H}^{+}(a q)+\mathrm{SO}_{4}^{2-}(a q) \longrightarrow \mathrm{CaSO}_{4}(s)+\mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)$

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Chemistry

Chapter 4

Stoichiometry of Chemical Reactions

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Video Transcript

this question says from the balance Molecular equations, right? The complete ionic and net Ionic equations for the following. And here ever it now the whole problem because it's a lot to write out that overthrew it. Uh, line by line. Here's the first bounce chemical equation. Here's the complete Ionic equation we have to potassium sze taskings have plus one charge. We have one sea to oh for mine Z to a four on which has a to my discharge. And then in this chemical, we have, uh, be a herbarium two. Plus, we have to Oh, h minus Science ko, which we have two potassium ions and 20 H. Minus science. And the solid is B A C 204 for the, um then the on equation. We're gonna take out a little accident, could take out all of the ions later the same on both sides of the equation. So there's potassium in hydroxide ions of both sides to be left with sea to oh for two months and be a two plus in the solid. As you mentioned for all of these questions, I didn't write a qu'est ce after all of the ions but all of the ions are in the estate and Toby in Ah, cause Chemical. The ions are PB two plus and, you know, three minus. And there are two of them Each dress. 04 we have each. Plus, there are two of them in S F or two minus one of them and in the products the Solidos PBS ofour And we have to each pluses. And two and a three minuses. And again for the simplified or the Net Ionic equation were to cross out the things that air in the reactions of the products. So there's two and a three minuses. It's also two protons. So we're left with PB two plus as before, to minus in the solid PBS afore See the joy one equally silly one set of ions. Here we have the solid csco three. Then we have to hide regions that have plus one you only have s a for two minus and then the products we have a solid C s, a four go to gas and h 20 liquid. And because there's only one set of islands in the entire reaction been that Ionic equation is the same. It's a complete ionic equation

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