The formula for this is $a = 2r_{Ca^{2+}} + 2r_{F^-} \cdot \sqrt{3}$, where $r_{Ca^{2+}}$ and $r_{F^-}$ are the ionic radii of $\mathrm{Ca^{2+}}$ and $\mathrm{F^-}$ respectively. Substituting the given values, we get $a = 2 \cdot 0.100 + 2 \cdot 0.133 \cdot
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