00:01
All right, so for this question, we're given the equations and there changes in entropy of those specific reactions in black.
00:10
And we're told we want to find a change in the entropy of the reaction in blue.
00:17
So how do we do this? well, we need to put the correct amount of reactants and products in the correct place.
00:24
So we know we need ch3oh liquid on the product side.
00:31
So we need to flip this reaction and therefore add instead of a specific.
00:37
Attract 726 .4 kilojoules per mole.
01:10
We also know that we need carbon in its graphite form on the reactant side.
01:17
So it's in the correct place.
01:18
So we keep this number the same.
01:33
So the heat of reaction is the same.
01:45
And we also know we need two parts of h2 gas on the reactant side.
01:54
So we'll have to double the enthalpy...