From the graph:h The total distance moved by the body =OB+BC+CD+DE+EF =6+(6-3)+(8-3)+(9-8)+(12-9

Name: Problem 12, Chapter 3: Physics Class 7
Uploaded: 2021-06-22T13:18:19-08:00
Duration: 59 s
Channel: Darshan Maheshwari
Description: From the graph:h The total distance moved by the body =OB+BC+CD+DE+EF =6+(6-3)+(8-3)+(9-8)+(12-9) =6+3+5+1+3 =18 m Total time taken (t)=16 s Average speed =( total distance )/( total time )=(18)/(16) m s^-1=9 / 8 m s^-1

step 1 Let's talk about question number 12. So in this case, we have to find the average speed and dist

Question

From the graph:h The total distance moved by the body $=\mathrm{OB}+\mathrm{BC}+\mathrm{CD}+\mathrm{DE}+\mathrm{EF}$ $=6+(6-3)+(8-3)+(9-8)+(12-9)$ $=6+3+5+1+3$ $=18 \mathrm{~m}$ Total time taken $(\mathrm{t})=16 \mathrm{~s}$ Average speed $=\frac{\text { total distance }}{\text { total time }}=\frac{18}{16} \mathrm{~m} \mathrm{~s}^{-1}=9 / 8 \mathrm{~m} \mathrm{~s}^{-1}$

   From the graph:h
The total distance moved by the body $=\mathrm{OB}+\mathrm{BC}+\mathrm{CD}+\mathrm{DE}+\mathrm{EF}$
$=6+(6-3)+(8-3)+(9-8)+(12-9)$
$=6+3+5+1+3$
$=18 \mathrm{~m}$
Total time taken $(\mathrm{t})=16 \mathrm{~s}$
Average speed $=\frac{\text { total distance }}{\text { total time }}=\frac{18}{16} \mathrm{~m} \mathrm{~s}^{-1}=9 / 8 \mathrm{~m} \mathrm{~s}^{-1}$

Physics Class 7

Trishna Knowledge… 2012 Edition

Chapter 3, Problem 12

Instant Answer

Solved by Expert Darshan Maheshwari

06/22/2021

Step 1

From the graph, we can see that the body moved from 0m to 6m, then from 6m to 3m, then from 3m to 8m, then from 8m to 9m, and finally from 9m to 12m. So, the total distance covered by the body is the sum of these distances. We can calculate it as Show more…

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From the graph:h The total distance moved by the body $=\mathrm{OB}+\mathrm{BC}+\mathrm{CD}+\mathrm{DE}+\mathrm{EF}$ $=6+(6-3)+(8-3)+(9-8)+(12-9)$ $=6+3+5+1+3$ $=18 \mathrm{~m}$ Total time taken $(\mathrm{t})=16 \mathrm{~s}$ Average speed $=\frac{\text { total distance }}{\text { total time }}=\frac{18}{16} \mathrm{~m} \mathrm{~s}^{-1}=9 / 8 \mathrm{~m} \mathrm{~s}^{-1}$

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Key Concepts

Distance Traveled

In kinematics, distance traveled refers to the total length of the path taken by an object, without regard to its direction. It is calculated by summing the absolute lengths of each segment of the motion.

Time Interval

A time interval is the period over which motion is observed. It is essential in calculating motion parameters because it represents the duration during which an object covers the given path.

Average Speed

Average speed is defined as the total distance traveled divided by the total time taken. It is a measure of how fast an object is moving overall, regardless of variations in speed during different segments of the motion.

Graphical Analysis in Kinematics

Graphical analysis involves interpreting graphs that represent motion, such as distance versus time graphs. By examining the segments and slopes of these graphs, one can determine distances covered, time intervals, and calculate parameters like average speed.

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