We can rewrite this equation as $(x+2)^2 + (y-3)^2 = 4$, which is the standard form of a circle equation $(x-h)^2 + (y-k)^2 = r^2$, where $(h,k)$ is the center of the circle and $r$ is the radius. So, the center of the circle is $(-2,3)$ and the radius is $2$.
Show more…