00:01
We're going to be talking about dl -h.
00:01
So in order to find out your dl -h is going to be your dl -h of your reactants.
00:12
We're not reacting.
00:14
It's the opposite.
00:18
Your delt -h are products minus your dl -h of your reactants.
00:29
And it would be how many moles you have of that reacting times your dl -h.
00:36
So in this case, for a, since you have one mole, of each of them, the mg -c -o -3, m -g -o and co2, then you multiply by one, which we'll leave it the same.
00:51
So when you look in the appendix b, you find that mgo is negative 601 .8, and you have to add that to your c -l -2, which is negative 393 .5 and you subtract that from your mgco3, which is going to be negative 1 .11 ,12 .9...