Question
From $x-y=0$ we have $y=x .$ Substituting into $3 x^{2}-4 y=0$ we obtain $3 x^{2}-4 x=x(3 x-4)=0 .$ It follows that (0,0) and $(4 / 3,4 / 3)$ are the critical points of the system.
Step 1
We are given two equations: 1) $x - y = 0$ 2) $3x^2 - 4y = 0$ Show more…
Show all steps
Your feedback will help us improve your experience
Hast Aggarwal and 77 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In Problems, find all critical points of the given plane autonomous system. $$ \begin{aligned} &x^{\prime}=3 x^{2}-4 y \\ &y^{\prime}=x-y \end{aligned} $$
Systems of Nonlinear Differential Equations
Autonomous Systems
The function has a critical point at (0,0) What sort of critical point is it? $$g(x, y)=x^{4}+y^{3}$$
Optimization: Local and Global Extrema
Critical Points: Local Extrema and Saddle Points
In Problems, find all critical points of the given plane autonomous system. $$ \begin{aligned} &x^{\prime}=x\left(1-x^{2}-3 y^{2}\right) \\ &y^{\prime}=y\left(3-x^{2}-3 y^{2}\right) \end{aligned} $$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD