00:01
So we want to use a 5 % significance level to figure out if these two people, larry and george, if they have a difference in the number of calls that are made.
00:13
And so we're going to assume, we'll call him one and call him two.
00:17
We're going to assume that the two are equal, that their number of calls that they make per day is equal, and alternately that they're different.
00:24
So we're not doing a direction test.
00:26
We're doing a two -tail test.
00:28
And we're going to be able to use z values.
00:29
So before i even write down the information, and their sample sizes are sufficiently large enough, so we want to have the 5 % split between the two tails, so 0 .025 and 0 .025 down here to add up 5%.
00:44
And we will be rejecting our null down here and rejecting the null down here.
00:50
And that z value will be 1 .96, and this z value is negative 1 .96.
00:56
So let's write down the data that we have for each of these two.
00:59
And we have for larry that larry has a mean of 4 .77 and has a standard deviation for his days, the number of calls being 1 .05.
01:13
And the sample size we have from larry is 40, 40 days of looking at his number of calls.
01:21
And for george, we have a total of 50 calls, or 50 days that we're looking at.
01:27
And his average over those 50 days was a mean of 5 .02 with a sample standard deviation of 1 .23.
01:37
Now, again, due to the fact that each of these is greater than are equal to 30, your textbook allows us to use a z value to estimate this.
01:47
Some books won't, but your book allows that.
01:49
So let's calculate that z value.
01:52
And so we will take the 4 .77 minus the 5 .0 .3.
01:57
So we can see our test statistic will be negative, and then divided by, and we need to put in our standard error for each of these two individually added together...