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In this video we're going to go through the answer to question number 2 from chapter 10 .4.
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So this question's in three parts.
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We're asked to give various periodic functions that are periodic versions of f of x equals sine of 2x on 0 to pi.
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So this function is drawn at the bottom of the page.
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It's just like a squashed up version of sign of x.
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So first up, part a, we have to find the pi periodic version of this function.
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The value at both ends of the, or off the limits, at both ends of the domain are the same.
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So you can imagine that we just continue this on to make the pi periodic version.
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And that'll just work out just fine.
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For all, except from the points that are circled, which are the integer multiples of pi.
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So f -tilda of x is just going to be a 2 -py version of f -fx, which is sign 2x, except that we're not defining it for k.
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Where k is an integer.
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Next part b, we asked to find an odd to pi periodic function that is the same as f of x on the domain zero to pi.
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So f odd of x, well to find out what this is going to have to be...