00:04
In this question, we have to find the maximum down poor rate it can handle for the galvanized drain pipe system.
00:14
So first, form the energy equation for this system.
00:17
It can be reduced to g -time z1 minus z2, or g -tam -h equals the loss.
00:27
If l over d, t, t, v, square, over 2.
00:30
Or we can see that v is equal to the square.
00:35
Square root of 2d g h y by l time f or it is just the square root of d g by f and this will be equation 1 so first we can make a guess for f to find the velocity v so f so f start with 0 .01 and then we can use equation 1 to find the value of b and that is equal to 9 .9 meter per second.
01:23
And we can find the renal number from d, vd over new, and that will be 4 .9 times 10 to the power of 5.
01:34
And we have that at this renal number, value of f is 0 to 64.
01:43
4 and then we can do it again for equation 1 to find the value of v which is 6 .09 meter per second and the number of 3 .01 times 10 to the power 5...