Question
Game of Craps In a game of craps, a player wins on the first roll if the player rolls a sum of 7 or $11,$ and the player loses if the player rolls a $2,3,$ or $12 .$ Find the probability that the game will last only one roll.
Step 1
The total number of possible outcomes is $6 \times 6 = 36$. Show more…
Show all steps
Your feedback will help us improve your experience
Richard Miller and 94 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The game of craps is played as follows: a player rolls two dice. If the sum is 2, 3, or 12, the player loses; if the sum is either a 7 or an 11, the player wins. If the outcome is anything else, the player continues to roll the dice until he rolls either the initial outcome or a 7. If the 7 comes first the player loses, whereas if the initial outcome reoccurs before the 7 appears, the player wins. Compute the probability of a player winning at craps.
Following is a description of the game of craps. A player rolls two dice and computes the total of the spots showing. If the player's first toss is a 7 or an 11 , the player wins the game. If the first toss is a $2,3,$ or $12,$ the player loses the game. If the player rolls anything else $(4,5,6,8,9 \text { or } 10)$ on the first toss, that value becomes the player's point. If the player does not win or lose on the first toss, he tosses the dice repeatedly until he obtains either his point or a $7 .$ He wins if he tosses his point before tossing a 7 and loses if he tosses a 7 before his point. What is the probability that the player wins a game of craps? [Hint: Recall Exercise 2.119.]
Probability
The Law of Total Probability and Bayes’ Rule
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD