00:01
Solution for the given problem here.
00:03
We have solution.
00:13
Here, given values for nitrogen monoxide.
00:44
The first one is partial pressure.
00:48
We have partial pressure.
01:00
Partial pressure of nitrogen monoxide here.
01:05
Partial pressure of nitrogen monoxide is equal to we have $22 .4.
01:14
Here we will convert tor into standard atmospheric pressure so here 22 .4 tor into 1 atm divided by 760 tor.
01:37
Here we will cancel the same units.
01:41
It is equal to we have the calculated value 0 .094 .0 .0 .940.
01:51
0 .029477m.
02:09
And next here, value is volume by t of nitrogen monoxide is equal to we have 335 -335 liter per second.
02:33
And next value is temperature for nitrogen monoxide.
02:38
Is equal to we have 955 kelvin and to solve this solution we have step one here by using ideal gas equation we can calculate n y t of nitrogen monoxide so here ideal gas equation is b b is equal to n r t and here we have partial pressure of nitrogen monoxide volume is equal to nrt.
04:03
And next is partial pressure of nitrogen monoxide and volume divided by t of nitrogen monoxide is equal to n divided by t of nitrogen monoxide...