00:03
So the first thing that we're asked to do in this question is to find the molar mass of this gas, which is composed of xenon and oxygen.
00:13
And the information that we're given, we have the mass in grams.
00:18
We want to get the molar mass in grams per mole.
00:20
So that means that we have to solve for moles.
00:25
So we're going to use the ideal gas law, pv equals n -r -t, which i'm going to rewrite as n equals pv over rt.
00:35
And the pressure is given as 0 .229 atmospheres.
00:42
The volume is 15 liters.
00:47
No, it isn't.
00:47
I'm looking at the wrong question.
00:50
The volume for this one is 0 .05 liters.
00:59
It's 50 milliliters.
01:01
So it's 0 .05 liters.
01:05
The r value is 0 .0821, because we're dealing with atmospheres.
01:20
And the temperature is 0 celsius, which is 273 kelvin.
01:26
So if we do this math out, we get 0 .000511 moles.
01:57
So i'm going to write that number down on a spare sheet of paper.
02:04
But now that we have that, we can take our 0 .1 grams and divide by our 0 .000 511 moles to get our molar mass of 195 grams per mole.
02:34
There's part a.
02:35
It's also asking us to find what the identity of the gas is.
02:39
So we know that it's composed of xenon and oxygen.
02:42
It's got to have at least one xenon atom, or else they would have told us it's oxygen.
02:47
Obviously, that's not the molar mass of oxygen.
02:49
So xenon has a molar mass of 131 grams per mole.
02:54
So once we take out our 131 for our single xenon atom, we can't have two xenon atoms because we don't have enough mass there to have two xenon atoms.
03:07
We take away our 131...