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Problem 94

An intermediate step in the production of nitric …

University of Maine

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Problem 93

Gaseous dichlorine monoxide decomposes readily to chlorine $(\text {green})$ and oxygen (red) gases.
(a) Which scene best depicts the product mixture after the decomposition?
(b) Write the balanced equation for the decomposition.
(c) If each oxygen atom represents 0.050 mol, how many molecules of dichlorine monoxide were present before the decomposition?


a. A
b. 2Cl2O (g)--> 2Cl2(g) + O2(g)
c. 1.8x10^23molecules



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Video Transcript

for the reaction in which gases die. Chlorine monoxide decomposes readily to form chlorine and oxygen gases. We have a compound breaking apart to make two new camp. Two new elements. Chlorine and oxygen are both die atomic elements, which means they exist as C. L two and 02 So in looking at the different reactions here in the products, what we're looking for are the elements that exist as two together, as opposed to these, which are single. So a best describes the products in terms of our numbers of oxygen's as O twos and are Koreans as CL tubes so we can write a balanced equation for this. Di chlorine monoxide means that it's to chlorine for everyone oxygen. So the formula for die corn monoxide is C L 20 as a gas form seal to gas plus o two gas. And when we balance the equation, well, we see on this side there are two chorines, and to Corinne's, this side there's one oxygen, but to oxygen's here. So we need to multiply the reactant by two, which then changes our product here. So that's the balanced equation. If this image here represents every oxygen is point 05 Moles of Oxygen. You can see that there are three of those molecules. So that means that we're reacting to form 0.15 Moves of oxygen describe how many molecules a c. L 02 is needed. For that we have to go from moles of 02 two moles of Cielo to two molecules using Allah God rose number. So we start off with their moles of 02 and then we use the ratio for the balanced equation which tells us for every one mole of 02 there will be two moles Feel too. Oh, and then we know that to go to molecules we use of a god rose number or 6.2 times 10 to the 23rd molecules for every mole. And this equals 1.8 times 10 to the 23rd molecules.

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