gaseous-phosphorus-pentachloride-decomposes-according-to-the-reaction-mathrmpcl_5g-rightleftharpoons

Question

Gaseous phosphorus pentachloride decomposes according to the reaction
$$\mathrm{PCl}_{5}(g) ightleftharpoons \mathrm{PCl}_{3}(g)+\mathrm{Cl}_{2}(g)$$
The equilibrium system was analyzed at a particular temperature, and the concentrations of the substances present were determined to be $\left[\mathrm{PCl}_{5}ight]=1.1 	imes 10^{-2} \mathrm{M},$ $\left[\mathrm{PCl}_{3}ight]=0.325 \mathrm{M},$ and $\left[\mathrm{Cl}_{2}ight]=3.9 	imes 10^{-3} \mathrm{M}$ . Calculate the value of $K$ for the reaction.

Anatole Borisov · Accepted Answer

So this reaction we has Bosphorous pencil chloride. You see all five as a gas right becoming PCL three also as a gas and seal to as a guess. And so we&#x27;re given the equilibrium concentrations of the cities. So at equilibrium we have PCL five is equal to 1.1 times 10 to the negative Second Moeller, we have PCL three is equal 2.3 to 5 Mueller and seal too is equal to 3.9 times tense and I give 30 more. And so since we have these contractors that equilibrium is we were asked to find Hey, we need toe right out the mass action expression for K and then plug in these values and so do that in purple or mass action expressions giving the product of the concentration of the products seal to PCL three over PCL five. So we have c l two PCL three the concentration of those There&#x27;s no power because they&#x27;re all to the coefficient of one Move PSL PCL five down here and now we plug in so 3.9 times 10 to negative third from here 0.3 to 5 over 1.1 time sense in your second. And when you do that, the value of K that you&#x27;re gonna get is 0.115 Now, remember, tase always you, Nicholas always. That&#x27;s just that&#x27;s just the fact That&#x27;s by definition way. So this is our final answer. The teacher tells you otherwise, um, they&#x27;re uninformed.

Evey Z · Answer

for this question. We don&#x27;t know the initial concentration for a react in order product, but we know that at equilibrium there are three times of a concentration of peace all five to piece all three. So if we give the concentration of PC or three with X than the concentration of peace 05 article liberum would be three X. And since we know that the product initial concentration are both zero and the change of PC, all three is X then according to a geometry, the change of concentration of seal to would also be X. Therefore the final concentration of sale Teoh out equilibrium with our so BX. And now, if we put down the equilibrium expression for this reaction, we would have k equals concentration of PCR three times concentration of C L two over concentration of peace l five and the equilibrium constant here is 6.3 times 10 to the minus four. And if we plug in the variables, we would have x times x over three X equals 6.3 times 10 to the minus four and x cancel out so x over three equals 6.3 times 10 to the minus floor and X would equals one point 89 times 10 to the minus stream off. And since we know that a seal to article Librium has the concentration of X, therefore still Teoh at equilibrium, concentration would be 1.89 times 10 to the minus three most.

Bin Chen · Answer

Okay, so I bring all the information given us for this problem in black. So the first thing that we should do is we should calculate decay for this reaction at equilibrium. So in order to calculate K, we need the concentration of all of you reacted to the products. So you must do that first, right? Concentration is concentration is most divided by leaders, right? We have leaders, but we don&#x27;t have most. Let&#x27;s calculate most. So we see that mo&#x27;s of PCL five is equal to 3.12 gram. Just how much we have divided by the molar mass. Right? So I&#x27;ve figured out the molar mass off all of these, and I&#x27;ve ruined them and read here. So we see that PCL five is to wait grams from Oh, all right, So we do that, we get point 015 most and Alice do most of PCL three. Tomoe of PCL three is equal to 3.845 grams, divided by the molar mass, which is 1 37 and we get plant 0 to 8 and then we go to most of of C L to get 1.787 divided by 71 which is 710.25 Most of those. So we figure out the most now we just got to find the concentration and we So we divide all of these most by the 10 leaders. Right here. We have concentration of PCL fa. Let me do you listen in different color, actually, you have concentration of p C. L five is equal to 0.15 moles divided by 10 leaders. We get playing 015 I m so m is my clarity. It&#x27;s most of out of my leaders now we have concentration of PCL three is 0.28 most wanted by 10 liters Get put 028 now for C l two. We have 20.25 moles divided by 10 years and we get 100.25 and right, So we figure out all the concentration at equilibrium so we can use these concentrations are equally well to figure out Ok, right, so okay is equal to the concentration of the products over the concentration of the reactant. Right? So we have PCL agree times it by CEO too, over concentration of PCL five. All right, so we modified this the concentration on the same side. But we divide by the other side. So we plug in the concentrations that we found from the low. You see that PCL three is point 0 to 8. Really? That c l two is 20.25 and we see that P C 05 is 0.15 All right, put that into the calculator. Would get K two b go two point. 0 4/7 Now this K we can use to find the answer. So they tell us that we&#x27;re adding 1.418 grams of seal, too into this equilibrium. So how would the eagle even be affected? Right. Well, if we were to add, we were increased CEO, too. Then the equilibrium was shift to the left. These will have more co two. So this more co two Well, uh, react with PCL dory to form or PCL five. Right? So the equilibrium was shift to the left. So, uh, they said that we add 1.418 grams of C l two and they want us to find the equilibrium concentration after we add it. So what we can do is figure out how many. What is the concentration of 1.418 grams of co? Two were much the same thing that we did in green and blue here. All right, so we have long points for 18 grams. We know that one mole of CO two is 71 grams Pramono, I&#x27;m gonna put ad right, and we get the answer as 0.0, to move. Now, let&#x27;s calculate concentration. Well, we know that concentration. We have add concentration seal to to go to a 0.2 moles over the volume, which is 10 years, and we get 100.2 Right? So what is the total number of C l two? We have Well, we have, actually, I don&#x27;t need this. Okay, so we add this concentration of C 02 to the already existing concentration. Right? So we know that at equilibrium making me a second I feel like So now we do do This is okay, So I c E o k. So we have 00.2 plus the concentration that we have right here just 0.25 and we get plenty 00 before five. So that is the concentration of CO two in our reaction. All right, so we have total concentration of co two. So we go up, we have we have points. Oh, for five for C E 03 We have 30.28 And for PCL five, we have 50.15 Right. So these are initial concentrations now. We gotta find the change in concentration. Well, we know that as your reaction proceeds, there will be so we know that the reaction shifts toe left. This means that Mawr PCL five will be forms we put plus X. We would from minus expert bolted these since all of these are 1 to 1 ratio in most. Right, So we have 111 Now we write the equilibrium expressions, we have 0.15 plus x, the plane. 0 to 8 minus X. And we have 0.0 for five minus x. This is a five here. Okay, so now we have decay that we calculated, right? And then we have these so we can use eso weaken, stop for accident. So we have from what we have 0.47 which is K. We have the same equally room expression, right? Well, we just have different values for concentration. Yes, we have t 0.0 to H minus X times it by 0.0 for five point. It&#x27;s x 0.15 plus x eso. When we saw for X, we should get X to be equal 2.0, for eight. Now we use the X and the equilibrium expressions right here to find the equilibrium. Concentration. Right. So we have Let&#x27;s see, for concentration of PCL five is equal to point a 15 plus X right. We know that X is equal 2.0 for eight. All right, so we get 0.198 as the concentration for PCL five PCL three We get 0.0 to H minus X. We know exes minus X. We know access 0.0 for eight, and we get 0.2 threes and then for CEO too. We have 0.0, 45 minutes X 450.0 for five minus 50.0! Four, eight Oh, it&#x27;s playing 00 for eight for all of these. But the answers are correct. I 80.0 for eight, and we get point. Oh! 0402 Okay, Yeah. Okay, so these these are answers to this question.

Ronald Prasad · Answer

for this question. Let&#x27;s sell for Mill Aridjis. First we of three point Well, let&#x27;s do this all at once. Um, polarity of PC of five. Initial. There&#x27;s going to be 3.1 to 0 grams and then the molar mass. It&#x27;s going to be too old, 8.5 grams per more, divided by one leader, someone leader flask. And this would give me went 0150 Moeller for the PCO five initial PCL three initial is going to be 3.845 We eat 45 grams on the molar mass. Just going to be 1 37.5 grams. Promote divided by one leader. This would give me point zero to eat zero Moeller and the clarity of seal to initial is 1.77 ground Spolar mouth 71.0 grams per mole. When a leader 787 but about 71.0 gives me 0.0 to 5 to Moller. So and then we&#x27;re told we&#x27;re gonna add 1.418 grams of seal too. So seal, too added, is 1.418 grams 71 grams per mole. Also in the one leader. Fosca, listen, Volume that&#x27;s not changing, but 71. And this would be 0.200 Moeller. So let&#x27;s set up a rights table here and we&#x27;ll get PCL five in equilibrium with PCL three and seal too. The initial uh, we just calculated we&#x27;ve got 0.150 0.28 and went 0 to 80 in 0.0 to 5 to. And so we&#x27;re gonna add 0.200 Moeller. So how the equilibrium be affected too, Right here. Uh, the addition of, um Siegel to causes the equilibrium to shift left. So we&#x27;re going to see a shift towards the left. The change here would be plus minus and minus. And we&#x27;re assuming that actually, these are present. Initially, we&#x27;re told at equilibrium. So let&#x27;s before we feel it filling the ice table. That&#x27;s all for my k value here, which would be PCL three seal too, over PCL five, which would be equal to 0.0 to 80 went 0 to 5 to and 0.150 slit self. Right, Librium constant. And we get point 0470 We&#x27;re gonna use that and will now solve X and calculate the equilibrium constant or the equilibrium values for everything once equilibrium has been reestablished. So here&#x27;s our expression. Going head in, solving for X we will get a quadratic that you may go ahead and verify. Uh, I&#x27;m gonna go ahead and solved, so point we use the same equilibrium. Constant. We&#x27;re gonna have 0.0 0.0 to 80 minus x and 0.0 45 to minus x. And we have 0.150 glass axe. So and find that the two routes we get our 0.1 or 0.115 and when 00 for 86 and we will have to will reject this route here is that will yield us negative values. And let&#x27;s go ahead and solve. So at reestablished PCO five at the reestablish equilibrium is 0150 plus explain 00486 and this will be equal to zero point 0199 Moeller PCL three. At equilibrium reestablished equilibrium is 0.0 to 80 minus 800.486 And this gives me 0.231 Moeller and C 02 at the reestablish equilibrium is 0.45 to minus X and we get 0.403 Moeller. So here are the three mil Aridjis once equilibrium has been reestablished.

Md Mohibullah · Answer

So in this problem, we&#x27;re given this reaction here and were given with the pressure pressure off each of the reactions and products and they could. Librium is in first part of this problem. We have to calculate the KP velo for this election. So first you have to write down the expression for the KP Velo for deceleration and expression will be the products. Partial pressure over the reactant pressure pressure that may be resealed. Five over. Be off BCL three times be off sale toe. So this is the equilibrium, constant expression in terms of pressure for duration given and we&#x27;re already given the values here, we just need to plug in the values so the people still buy Bello is one burnt three and then, um partial pressure of pc All three his 0.124 times the pressure pressure off sealed too, which is 0.157 And from here, just solving this you can find the Vela off KP which is 66 point 776 and this is the GP velo for the reaction given now, in part B of this problem, we have to say if they kill me and will favor reactant our products. So from the cool room, constant below, we can see that the fellow is ah, very large than one. And as they know that if they can ever be inconstant fellow is very larger than one. That means that equilibrium will favored the products. And that&#x27;s why in this reaction day, Caribbean will favour the product peace. He&#x27;ll fight. And then in c part of this problem, we were asked to find out where calculate the kiss he velo for this reaction. So we know that there&#x27;s a relation between keeping and kiss each escape physical toe. You see, Artie Dill and where cape is the clear inconstant in terms of pressure kisses the equilibrium constant in terms of concentration in majority are is there anywhere still gas constant and is the a fellow of the temperature in Calvin skill on DH Until N is them, um, value off the difference of the number of molecules of products and Americans. So here we know the value ofthe KP, which you have just calculated. We know the well off are which is a constant, and we know the value ofthe the so the well off B here is giving us for 50 game and we know the veil off our as zero point 02 or six Leaker. Kampar mole Calvin. So now we just need to know the value of Dylan and from the balanced equation. You can see that the number of monoliths of products is one, and the number of molecules off reactions is one plus one, which is too. That means the number ofthe molecules are the fellow off. Till in here is one minus two, which is minus one. So if we just so that fellow Dylan here is minus one now if we just rearrange thiss question will be we can find the veil off. Casey has been putting K p over Artie, hold the board l n. So the value of K piece calculating 66.776 and the well off our is zero point 0 to 1 times the value ofthe temperature, which is for 50 care. So we have to make sure I remember that the temperature value is always in Kelvin. So if it is given in degrees Celsius, we have to convert it to Calvin skill just by adding to 73 toe the Davises Velo, and we&#x27;re given on a calculated the value of Dylan as minus one. So if he&#x27;s solved, this will get the value ofthe case. Years 2.467 times into the poor, minus three. So this is the fallow off Casey for the reaction, give them.

Ronald Prasad · Answer

It&#x27;s hardly the equilibrium constants. Let&#x27;s first define it. It&#x27;ll be equal to PC Off Similarity PCL three. I&#x27;m Similarity A Sealed You in the numerator divided by the Malaria PCL. Five. In the denominator we have these values. So let&#x27;s go ahead and put them in. Um, Larry PCL three is 1.3 times in the negative, too. P c R C L two is 3.9 times 10 to the negative three and PCL five is 4.2 times 10 to the negative five. And our equilibrium constant here would work it out will be equal to 1.2 uh, just 1.2.

Problem

Write the equilibrium expression for each of the …

Problem 99 Medium Difficulty

Answer

$\mathrm{K}=0.115$

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$\mathrm{K}=0.115$

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Steven S. Zumdahl, Donald J. DeCosteIntroductory Chemistry

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