00:03
Okay, what we have here is three equations and what we want to do is we're going to use the bond energies to calculate delta h for each of the reactions.
00:11
The first one we have is h2 plus cl2 produces 2hcl.
00:20
So what we're going to do is write down the bond energies of each of these and h2 is going to be 436 and cl2 is going to equal 243.
00:35
And we have hcl.
00:36
Hcl is going to be 431 but since there are two of them we're going to multiply it by two.
00:43
Now, we're going to add these all up together.
00:46
These require energy to break, however when this is formed it releases energy so that's going to be a negative.
00:53
So when we add this all up together we get a negative 183 kilojoules per mole.
01:02
Alright, for the second one we have h2 plus i2 produces 2hi, a very friendly molecule there.
01:13
And once again this is going to be 436.
01:16
The i, however, is going to be 151 and the hi is going to be 297.
01:25
But once again there's two of them so we're going to multiply it by two and since we are forming this it's going to release energy so we make it a negative and that is equal to a negative 7 kilojoules per mole...