00:04
We're given a subset s of the set of ordered pairs of integers defined recursively by basis step.
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Zero zero, border pair lies in s.
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And recursive step.
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If a, b, lies in s, and a plus 2, b, plus 3 lies in s.
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This is the most, this is the best you live is going, is the most you're depressed.
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And 8 plus 3d plus 2 lies in s.
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Well, how about this? i don't want to talk about it anymore.
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In part a, we're at the limit list the elements of s produced by the first five applications of their cursive definition.
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So in the first application.
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Well, all we have to do is apply to a curse except on zero -zero.
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So we have zero plus two, zero plus three is equal to two -thirty.
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Two -thirds.
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You wouldn't suck your grandma's dick if she asked you to.
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And zero plus three, zero plus two equals three -two.
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Also lies in s.
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I think one time, but it wasn't molestation.
01:37
One time me and my cousin.
01:39
Now on the second application, well now we have to apply their cursive step on two three and three two.
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So we have two plus two, three plus three plus, which is four, six.
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We have 2 plus 3, 3 plus 2, which is 5, 5, which is also in s.
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We have 3 plus 2, 2 plus 2, which is again 5 5, 5, the same as above.
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And we have three plus three two plus two, which is six four, which lies in us.
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So we generate three new elements in this step.
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Then in the third application.
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Third application.
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Well, now we're applying this on the elements.
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4 -6 -5 -5 -6 -4.
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He painted a fucking mural and spray paint on the back of this fucking p.
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Yeah, that's cool.
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I'll take a picture of this out home.
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Anyway, yeah, i just asked.
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It reminds me of the pjs.
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You ever see the pjs? yeah.
03:18
Oh, yeah.
03:18
They had a joke.
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So we have four plus two, six plus three, which is six, six, six.
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9.
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That was a good show.
03:27
That was a very good show.
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As well as 4 plus 3, 6 plus 2, which gives me 7 8.
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5 plus 2, 5 plus 3, which gives me 7 8 again.
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5 plus 3, 5 plus 2, 5 plus 2 which gives me 8 7 then 6 plus plus 3 to be molested was that my dad just was constantly naked around me my tire up right which is 8 -7 again and 6 plus 3 4 plus 2 which is 9 6 and so a nice this step we generate the four pairs, 69, 7, 8, 7, and 96.
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Now in the fourth application, we apply the induction rule on 69, 7, 7, 7, 7, 7, 7, 8, 7, 7, 7.
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And nine six we have six plus two nine plus three give me eight twelve six plus three nine plus two is nine eleven and 7 plus 2, 8 plus 3.
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This is also 9 -11.
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7 plus 3, 8 plus 2, which is 10, 10.
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Okay, so you have a real.
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Actually, i walked in on my dad jacking off on time.
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Then 8 plus 2, 7 plus 3, which is also 10, 10.
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8 plus 3, 7 plus 2.
06:01
Which is also, well this is 11 9.
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And finally, and finally, 9 plus 2, 6 plus 3, which is 119, which you've already seen.
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And finally, 9 plus 3, 6 plus 2, which is 12, 8.
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So we generate the five new elements.
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812, 9, 11, 10, 10, 11, and 12, 8 ,000, and 12, 8.
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Finally, in the fifth application, we want to imply the inductive step to our five new members.
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812, 9, 11, 9, 11, 10, 10, 11 9, and 12, 8.
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We were saying, i was a hotel room, my parents had one room, my sister had a room and i had a room next door.
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We had 8 plus 2, 12 plus 3, which is 10, 15.
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8 plus 3, 8 plus 3.
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12 plus 2, which is 1114.
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9 plus 2, 11 plus 3.
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9 plus 2, 11 plus 3.
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This is 11 14 again.
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9 plus 3, 11 plus 2...