Question
Geometric Mean The geometric mean of two positivenumbers $a$ and $b$ is $\sqrt{a b}$ . Show that for $f(x)=1 / x$ on anyinterval $[a, b]$ of positive numbers, the value of $c$ in theconclusion of the Mean Value Theorem is $c=\sqrt{a b} .$
Step 1
Step 1: We are given the function $f(x) = \frac{1}{x}$ and we are asked to find the value of $c$ in the conclusion of the Mean Value Theorem on the interval $[a, b]$. Show more…
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