The volume of a cube is given by the formula $V = a^3$, where $a$ is the length of the edge of the cube. In this case, $a = 565 \, \text{pm} = 565 \times 10^{-12} \, \text{m}$. Therefore, the volume of the unit cell is
\[V = (565 \times 10^{-12} \, \text{m})^3 =
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