Question
Give a counterexample to disprove each statement, where $\mathrm{P}(x)$ denotes an arbitrary predicate.$$(\exists x) P(x) \rightarrow(\exists ! x) P(x)$$
Step 1
The statement says that if there exists an $x$ such that $P(x)$ is true, then there exists a unique $x$ such that $P(x)$ is true. Show more…
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