00:01
So looking at this problem, we have the ordered pair negative 1 to 8, and then we have the ordered pair 1 -2 with a horizontal asymptote at the x -axis is what it looks like to me.
00:22
Oops, i forgot to write down 1 -2.
00:24
So if we're looking at that form, y equals a times b to the x, what i would probably do is set up a system of equations where when y is 8, x was negative.
00:39
Of 1 and then when y was 2, which replaced in that, i have x was 1.
00:46
So what i could do with both of these is i could solve for a by dividing b to the negative first over on that one is equal to a.
00:55
And same thing with this one, 2 divided by b to the 1st is equal to a.
00:59
The reason why i would do that is then i can solve, set the equations since they both equal a, they must equal each other.
01:09
Now, 8 divided by b to the megaphrst is the same thing as 8 times b is equal to 2 over b...