00:01
For this problem, we're asked to give a possible set for the four quantum numbers for the 4s and the 3d electrons in titanium.
00:17
And first we want to remember what those quantum numbers are.
00:22
So we have n, which is the principal quantum number, and that relates to the size and energy of the orbit.
00:33
We have l, which is the angular momentum, which can be any number that is 0 to n minus 1.
00:52
Then we have m subset l, which is the magnetic quantum number.
01:02
And that can be from negative l to positive l including zero, and that's the orientation of our orbit.
01:17
And then we have ms, which is the electron spin, which can only be negative one -half or positive one -half.
01:29
So first thing we want to think about is let's do 4s first.
01:37
So for 4s, what is a possible set of quantum numbers we can have? well, since n is the principal quantum number, and that corresponds to your orbital, that can only be 4 because it is 4s.
01:55
L, since it is an s orbital, it's going to be zero.
02:00
Our angular momentum has to be a zero.
02:02
Again, that's the shape of the orbital, and since it is an s orbit, it's going to be zero...
