00:05
The higher data of the compound is given 3020, 2965, 2940, 2870, 2870, then 1517, 1468 and 818.
01:07
The enema data indicates 1 .2 doublet, approximately 3 protons, probably 6 protons, 6 protons, double it of 6 protons, a 2 .3, a single act of 3 protons, and then 2 .8, a septet of 1 proton, and then 7 .0, 7 .1, a multiply approximately 4 protons.
02:54
The monocular formula of the compound is c10 h 14.
03:18
Now we'll assign the structure of this compound.
03:34
We'll assign the nmr signals first.
03:43
This will be a ch3 twice c.
03:52
This would be a ch3...