00:02
In question number 44 give a structure of each of the following.
00:10
So a is cyclobutin.
00:13
So we have to make this structure of cyclobutin here.
00:16
Cyclobutin, 4 carbon atoms and cyclic ring.
00:22
So we can draw it like this and double bond.
00:33
Double bond must be present because en is indicating it.
00:37
So double one we can draw here this is cyclobuty now come to second one three methyl one octane one octane not cyclo so we are making the structure one two three one two three four five six seven eight octet, 1, 2, 3, 4, 5, 6, 7, 8.
01:24
Total 8 carbon atom, octene, 1 octane, that means the first carbon should have the double bomb.
01:34
First carbon is this one.
01:36
And 3 methyl, 1, 2 and 3...