Give each of the structures in Exercise 13.5 an IUPAC name....

Name: Problem 6, Chapter 13: Chemistry for Today: General, Organic, and Biochemistry
Uploaded: 2020-02-03T02:11:01-08:00
Duration: 3 min 17 s
Channel: Amy Jiang
Description: Give each of the structures in Exercise 13.5 an IUPAC name.

Key Concepts

IUPAC Nomenclature

IUPAC nomenclature is the standardized method for naming organic compounds, established by the International Union of Pure and Applied Chemistry. It ensures that each compound has a unique and systematically derivable name that reflects its structure, facilitating unambiguous communication in chemistry.

Parent Chain Identification

This concept involves determining the longest continuous chain of carbon atoms in a molecule, which serves as the backbone for its name. The parent chain sets the base name of the compound, with substituents and functional groups added as prefixes or suffixes according to their positions.

Substituents Identification and Locants

After identifying the parent chain, any additional groups attached to it (substituents) must be recognized and assigned numerical positions, known as locants. This helps in accurately describing the location of each substituent along the chain, which is crucial for distinguishing isomers.

Functional Group Priority

When multiple functional groups are present, specific rules determine their priority in the naming process. The most functionally significant group often defines the suffix of the compound's name, while others are treated as substituents, with their positions indicated accordingly.

Stereochemistry

In cases where compounds have chiral centers or geometric isomers, stereochemical descriptors are used to indicate the spatial arrangement of atoms or groups. This aspect of nomenclature ensures that the three-dimensional configuration of a molecule is communicated clearly.

Transcript

00:01 All right, so for this question, we're asked to name the following structures.

00:05 And for part a, we have this following structure.

00:08 So let's count the number of carbons in the longest chain.

00:12 We have one, two, three, four, five.

00:15 So since we have five, we know that this is a pentane.

00:20 So let's write that at the end.

00:23 We know this is a pentane because it's just a single bond.

00:28 And yeah, it's a single bond between every.

00:32 Carbon and hydrogen.

00:34 And let's see, we know that the ch3, this is methyl, and it's in position two.

00:40 So what we have to do is write to methyl and then the pentane.

00:46 So that's the name of our first structure.

00:49 Now for our second one, for part b, we have the following structure.

00:52 So let's count our number of longest chain carbon.

00:56 So that's one, two, three.

00:58 So since we have three longest chain carbons that is propane and they're all single bonds.

01:06 And then if you notice there are two um sub situational groups attached to that and this is methyl but since there are two of them, we put a dye in front and then so it's two dye methyl propane.

01:26 Actually we need to do two to to say it are position of both of them.

01:30 All right and lastly we have part c which is as we can see this is a ring structure.

01:36 So we know that we're going to have to add cyclo before the name of the longest chain, which is our ring structure...

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