00:01
Okay, so we're asking of the eight isomers of a 5 carbon chain with an alcohol attached to it.
00:06
So the first one, we can start by putting the alcohol at the end of the 5 carbon chain, and then just move the alcohol.
00:19
So putting it on carbon 2, and then carbon 3.
00:25
So we can't put it on this carbon, otherwise it would be 2 petanol.
00:29
We already have the structure right here.
00:32
Another thing we can do is decrease the carbon chain by 1.
00:35
So we're going to use butanol, putting the alcohol right there.
00:39
First and putting the methyl group right here.
00:41
We can't put the method group right here because it would be two pentanyl, one, two, three, four, five, and we already have the structure.
00:52
So that's to get right there.
00:56
So leave the alcohol, move the methyl group.
00:58
This will be one, two, one, two, three, and it's all we can do there.
01:04
We can move the alcohol now.
01:07
So putting the alcohol, and methyl on the same carbon, doing that, and also moving the methyl group.
01:26
So this is going to be, so the alcohol has priority over the methyl.
01:30
This is going to be three methyl and two butanol, as opposed to this one, which is, actually, never mind.
01:49
So it's the same thing as the other one...