00:01
So in this problem, we are going to first draw the skeletal structures as shown based off of these structures given.
00:11
So remember that in the skeletal structures, there are carbons at the ends of the lines and in the corners.
00:16
And each of the carbons are assumed to have a total of four bonds.
00:18
So we need to assume that the carbons are bonded to the number of hydrogens that will complete the requirement.
00:25
So for the first one, we need to find the longest carbon chain.
00:32
If we count the longest carbon chain, we find there are seven carbons.
00:35
So therefore, this is going to have the base name heptane.
00:39
And then there are three methyl substituents.
00:42
You need to number the carbons so that the substitutions have the lowest numbers possible.
00:47
So we start from the left.
00:48
We go one, two, three, and we have two of them on the third carbon.
00:51
And we have five, and we have one methyl group on the fifth carbon.
00:56
So it's 335 trymethyl heptane.
01:00
So then for b, we start...