00:01
So in this problem, give iupac names for the following compounds.
00:09
So we can refer to these nomenclature rules.
00:14
So we need to find the longest carbon chain.
00:16
For the first one, the longest carbon chain ends with being pentane.
00:20
We have one methyl substituent on the second carbon.
00:26
So therefore, it's going to be two methylpentane.
00:29
And remember, we always name the carbon so that the carbons have the lowest numbers possible.
00:36
So for b, you have two methyl groups.
00:42
On the second carbon.
00:43
The longest chain has four carbons, so that's butane.
00:48
So we need to put a dye in front of the methyl because there are two of them.
00:52
And remember that we number the carbons so that the substituents have the smallest numbers possible.
00:57
So it's 2 -2 -dymethyl butane...