00:01
In this problem, we need to give the iupac name for this molecule, including stereochimistry in the name.
00:06
So the first thing you need to do is establish your root, which is the longest chain of carbons that you have.
00:11
And the root for this one is heptane, because we have our longest continuous carbon chain is seven carbon.
00:18
I'm just going to label those real quick, so we don't get them messed up.
00:28
At the two position, we have a bromo group.
00:34
And at the five position, we have an ethyl group.
00:38
So now we need to figure out the stereosific configuration for this bromine.
00:46
So you need to start by assigning con angle prelog priorities.
00:52
So the highest priority group is going to be bromine because it has the highest atomic number.
00:56
The second highest priority group is going to be the larger alpha group because it's attached to more carbons.
01:03
The third is going to be this methyl group over here.
01:07
And the lowest priority group is always going to be hydrogen if there's a hydrogen attached.
01:10
So the next thing you want to do is you want to count from 1 to 2 to 3.
01:15
And if it's going clockwise, it's going to be an r configuration.
01:19
If it's going counterclockwise, it's going to be an s configuration.
01:23
So the hydrogen was already pointed away from us, which is what we need.
01:26
You need the lowest priority group pointed away from you.
01:29
So going from 1 to 2 to 3, it's clockwise.
01:33
So it's going to be our iupac name is going to be 2r, bromo, 5, ethel, peptine.
01:57
It gets a little bit more difficult.
02:00
So our molecule this time involves two stereocenters.
02:14
Okay, so our root for this one is going to be cyclocintane...