00:01
Let's now solve the problem from the chapter, chemistry of life, organic and biological chemistry.
00:06
Here in this problem, we have to give the molecular formula of a cyclic alkyne, cyclic alkyne, linear alkyne and an herometric hydrocarbon, having six carbon atoms.
00:19
So let's give the formula one by one.
00:22
With six carbon atom, the cyclic compound, simplest cyclic compound can be represented as ch2, ch2, ch2, ch2, ch2, ch2, ch2, ch2, ch2, ch2.
00:39
Six carbon atoms are arranged in the form of a cyclic ring with each carbon atom bonded to two hydrogen atoms.
00:46
So we can see that there are six carbon atoms and 12 hydrogen atoms in all.
00:51
So the molecular formula of the compound is c6h 12.
00:56
The next one is cyclic alken.
00:59
In alkenes, we know that double bond between carbon carbon is present.
01:04
So here, cyclic alken having a double bond between two carbon atoms can be represented as six carbon atoms arranged in the form of ring.
01:14
We are four carbon atoms have two hydrogen atoms bonded to them each and the other two carbon atoms are joined to each other by a double bond and contains one hydrogen atom.
01:25
So we can see that in this structure there are six carbon atoms.
01:29
Atoms and 10 hydrogen atoms.
01:33
So the cyclic alkyene with six carbon atoms has the molecular formula c6h 10.
01:41
The next one we have to write is for linear alkyne...