- The substrate is $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CHBrCH}_3$, a primary alkyl halide.
- The reaction is likely an $\mathrm{S}_\mathrm{N}2$ mechanism due to the primary nature of the carbon attached to the bromine.
- The product will be $\mathrm{CH}_3
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