Problem

Indicate the coordination number for the central …

05:44

Problem 25 Hard Difficulty

Give the oxidation state of the metal for each of the following oxides of the first transition series. (Hint: Oxides of formula $\mathrm{M}_{3} \mathrm{O}_{4}$ are examples of mixed valence compounds in which the metal ion is present in more than one oxidation state. It is possible to write these compound formulas in the equivalent format $\mathrm{MO} \cdot \mathrm{M}_{2} \mathrm{O}_{3}$, to permit
estimation of the metal’s two oxidation states.)
(a) $\mathrm{Sc}_{2} \mathrm{O}_{3}$
(b) $\mathrm{TiO}_{2}$
(c) $\mathrm{V}_{2} \mathrm{O}_{5}$
(d) $\mathrm{CrO}_{3}$
(e) $\mathrm{MnO}_{2}$
(f) $\mathrm{Fe}_{3} \mathrm{O}_{4}$
(g) $\mathrm{Co}_{3} \mathrm{O}_{4}$
(h) $\mathrm{NiO}$
(i) $\mathrm{Cu}_{2} \mathrm{O}$

Answer

a) Hence, the oxidation state of scandium is $[+3]$
b) Hence, the oxidation state of titanium is $[+4]$
c) Hence, the oxidation state of vanadium is $[+5]$
d) Hence, the oxidation state of chromium is $[+6]$
e) Hence, the oxidation state of manganese is $[+4]$
f) Hence, the oxidation state of iron in $\mathrm{Fe}_{3} \mathrm{O}_{4}$ is $[+2]$ and $[ +3]$
g) Hence, the oxidation state of cobalt in $\mathrm{Co}_{3} \mathrm{O}_{4}$ is $[+2]$ and $[ +3]$
h) Hence, the oxidation state of nickel is $[ +2]$
i) Hence, the oxidation state of copper is $[+1]$

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Chemistry 102

Chemistry 101

Chemistry

Chapter 19

Transition Metals and Coordination Chemistry

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Video Transcript

for auction. E Let the oxidation state off S E two or three B x. The overall compound doesn't have any oxidation state the general oxidation state off. Oxygen is negative toe subsidies substituting in the values the oxidation State offs Candy, um, is plus three for option B. Let the oxidation state off. Titanium B X. The compound doesn't have any overall oxidation state on the oxidation. State for oxygen is negative, too. Substituting in the values the general oxidation state off. Titanium is blissful oxidation, state off brandy and B X oxygen will be negative too, substituting in the values we have. Bandy um, oxidation state equals plus five oxidation. State off chromium will be X By that off, oxygen will be minus two. Substituting in the values ex turns out to be plus six, that is the oxidation state off chromium for auction E oxidation state off. Magnus will be ex toe that off excision, too. Using the oxidation state off magnesium turns out to be plus four for option. If the idea Knox side is mixed, Excite comprising off a few and f ree tau tree led the oxidation state off island in f b o B X on oxygen oxidation state is minus two, substituting in the values ex turns out to be plastered for oxidation. State off F E to one tree. Item is X on oxygen is minus two, substituting in the values the oxidation state off island in f eet watery, this blustery for last option. Let the oxidation state off Kobach be ex in both the cases, substituting in the values the oxidation. State turnout Toby plus two on Blustery.

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