00:02
So in this question, we want to determine the oxidation state of the metal, which is cobalt, right? and the number of d electrons and the number of unpaired electrons.
00:19
So first oxidation state of the metal in this complex.
00:29
Now, the ligand ammonia is neutral, right? so that doesn't count the oxidation states.
00:39
So if you have three of chloride, we know that chloride is minus one.
00:46
Okay.
00:47
So it means that oxidative state is calculated as kubalt, which is x plus minus 1 times 3 of the chloride.
00:57
It goes zero.
00:59
Right.
01:00
So it means that x equals plus 3.
01:04
Okay so this is cobalt 3 plus okay cabote 3 plus now let's look at the yeah so that's the oxidation state and then number of the electrons to determine the number of the electrons we need to know the electron configuration now the neutral cobalt the electron configuration is argon for has 2, 3d7.
01:45
Okay, so it implies that if we have cobalt 3 plus, it lost three electrons.
01:54
So the d of which i lost three electrons.
01:57
So this one is 3d, the number of the electrons will be 7 minus 3, which is 4.
02:08
So it's 3d4.
02:12
Okay.
02:14
Now, the number of the impaired electrons, we use the crystal field theory.
02:22
So the diorbital splits, and that depends on the ligand.
02:27
The ligand is ammonia, which is strong field...