00:01
For this problem, they're first asking us what the difference in displacement is or what our displacement is.
00:07
My fact, that our displacement is between 0 and 2.
00:11
So we're giving the function for position as equals t squared minus 3t plus 2.
00:18
So to find the difference in position, we'd plug in the endpoints and then subtract final minus initial.
00:25
So if we plug in 2, we'd get 4 minus 6 plus 2.
00:30
And this would equal 0.
00:32
If we plug in 0, we would get, sorry, dash point here, separating them.
00:38
We would get 0 minus 0 plus 2 equals 2.
00:41
So that means our final minus our initial would be negative 2.
00:47
So our change in displacement would be negative 2 meters.
00:52
And as for our average velocity, we calculate this by finding our final plus our initial divide by 2.
01:00
So to find a velocity, we need to take the derivative of this, and this would give us v of t.
01:09
Once we take the derivative equals 2t minus 3.
01:14
So once we do that, we plug in 0 and 2, and we get that the final one, which is if you find t equals 2, it would be 4 minus 3.
01:25
So that would equal 1 plus the initial one, which be 2 times 0, which is 0, minus 3 would be negative 3 over 2, this value equals negative 2 over 2, which equals negative 1 meters per second...