Give the product of the reaction of methyl bromide with each...

Give the product of the reaction of methyl bromide with each of the following nucleophiles:
a. HO $^{-}$
b. $^{-}\mathrm{NH}_{2}$
c. $\mathrm{H}_{2} \mathrm{S}$
d. HS $^{-}$
e. $\mathrm{CH}_{3} \mathrm{O}^{-}$
f. $\mathrm{CH}_{3} \mathrm{NH}_{2}$

Key Concepts

Leaving Group Ability

The leaving group's ability is crucial in substitution reactions. A good leaving group, like bromide, is capable of stabilizing the negative charge when it departs from the substrate. The quality of the leaving group affects the ease of the bond cleavage during the SN2 process, making reactions more favorable when the leaving group is stable once it has left the molecule.

Nucleophilicity

Nucleophilicity refers to the strength or ability of a species to donate an electron pair and form a new chemical bond with an electrophile. In SN2 reactions, the rate depends on the nucleophile’s strength and its concentration. Different nucleophiles, such as HO?, NH??, CH?O?, and HS?, have varying nucleophilic strengths and behaviors that influence the reaction rate and outcome.

SN2 Reaction Mechanism

The SN2 reaction is a bimolecular nucleophilic substitution mechanism where the bond formation between the nucleophile and the electrophilic carbon and the bond breaking of the leaving group occur simultaneously. This single-step process leads to inversion of configuration at the carbon center and is most favorable for primary and methyl substrates due to minimal steric hindrance.

Alkyl Halides

Alkyl halides, such as methyl bromide in this case, serve as electrophilic substrates in nucleophilic substitution reactions. Their polarized carbon-halogen bond makes the carbon atom vulnerable to attack by nucleophiles. Methyl halides are particularly reactive in SN2 reactions because of their small size and the lack of steric hindrance, facilitating backside attack.

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