00:02
Suppose we want to predict these products.
00:06
Well, let's take the first reaction.
00:08
We have a benzonitral reacting with methyl chloride in the presence of our lewis acid catalyst.
00:14
Well, this reactant should automatically tell us that we are looking at friedelcraft's alkylation.
00:24
So we need to make sure that we have an orthoparadirecting group on our benzene.
00:29
In other words, we need to make sure we have an electron pushing or an activating group.
00:35
And if we look at this one, we have nitral.
00:39
Now, nitral has a triple bond.
00:44
And when it engages in resonance, one of those bonds goes onto the nitrogen.
00:52
And the electrons from the benzene makes a double bond with the carbon.
00:58
This tells us that it's electron withdrawing, not electron pushing, which means that it is a deactivating group.
01:06
And therefore meta -directing, which also means that it will not undergo fidelcraft's alkalation.
01:20
Let's try this example.
01:22
Fenol reacted with bromine.
01:25
Now, right off the bat, it kind of looks like there would not be a reaction because there is no catalyst, right? however, alcohols, and to that extent, ethers are very, very strong electron pushing groups.
01:48
In fact, they would push their electron pairs into the benzene ring really well and would donate those electrons and kind of activate the benzene ring, which makes it an activating group, which makes it orthopara directing.
02:07
And because it's so strong, it doesn't need a catalyst for this reaction to occur.
02:13
And since it's ortho -paradirecting, we'll have our two products...