00:02
Here just you have to draw the structure's name is already given in the question.
00:10
So first is a that isopropyl bromide.
00:17
Isopropyl bromide is ch3 ch ch ch ch b.
00:38
This whole group is known as isopropile that is why this compound is isopropyl bromide.
00:47
Now come to b 3 bromo 4 ethyl heptane hapton is the basic compound so you are writing that first 1, 2, 3, 4, 5, 6, 7 3 bromo, 3 carbon 4 ethyl 4th carbon ethyg group c2h5 have 10 total 7 carbon atoms in the chain remaining valencies of carbon satisfied by hydrosy.
01:38
So here ch3, this should be ch2, then only one hydrogen, ch, ch2, ch2, ch2, ch3, with the structure of b.
01:57
Now come to c.
02:01
C should be 1 -1 -dichloro 2 -mythyclohexy.
02:11
Cyclohexia is this compound.
02:26
1 -1 -dichlor.
02:29
First carbon if this one is the first one, di -chloro, 2 chlorine groups are present here.
02:37
2 -mythi.
02:39
2 -methy.
02:39
2 -carbon is having me so c -h -3.
02:48
1 .1 dichloro 2 methyl cyclohexine.
02:53
This should be c.
02:55
Now come to d.
02:59
D is trans 1 chloro, 3 iodos cyclobuty.
03:07
Cyclobutane.
03:09
That means it should be this compound.
03:20
Trans 1 chloro, 1 position is this one.
03:34
Chlorine is here.
03:36
3 iodope 3 iodine.
03:40
Third carbon iodos cyclobutin.
03:49
If chlorine is here above the plane, iodos should be below the plane.
04:02
And that is how this transposition of chlorine and iodope in the compound.
04:10
So this is the structure of d...