00:01
Hello friends, now i will tell you how to give the substitution product for the given compounds.
00:10
The first compound is two chloro, two chloro two methyl, three hexene, and the other compound is three bromo, one methyl cyclohexene.
00:24
So friends, now what will be the substitution of this product when we will dissolve it in the? solution of sodium acetate when we will add this compound to the sodium acetate dissolved in the acetic acid solution what will be the substitution product so for that purpose i need to convert the naming into the structure so we should go with the first compound two chloro two methyl three hexine so friends i will draw the structure for you first so that it will be easy to draw the final product okay let's say a position there must be a chloro c and then double want you should do the right the configuration right okay ch2, ch2 and then ch3.
01:48
So this is your first compound to chloro2 methyl 3 hexine.
01:56
Okay, when it is added with sodium acetate dissolved in acetic acid, you know that sodium acetate in the acidic acid, you know that sodium acetate in the acidic acid, you know that sodium acetate, in the acidic acid.
02:12
Acid will be like this see the bulb and it oh okay or negative then na positive okay so now you can see that the sodium ion this one is a good nucleophile and as we know that in s mucidase the the nucleophile will attack on the carbon center which is directly attached to a halogen group so that it will substitute the halogen and the halogen will be removed from its position and the upcoming nucleophile will take the position...