00:01
In this problem, we will name the compounds i've drawn below.
00:06
When naming compounds, it is best to start by numbering the parent chain, or the longest chain, in the alkan.
00:14
Next note, which carbons have the substituents.
00:19
In our case, we have a methyl group on carbon 2 and 4.
00:23
So the name of this 2 and 3, we have methagroups on carbons 2 and 3.
00:27
So the name of this molecule would be 2, 3, dimethyl, butane, where bute signifies that you have a 4 -carbon chain and the dye indicates 2.
00:47
Now let's look closely at our second molecule.
00:53
We number the chain.
00:54
We have the same number of carbons, whether we go from the left or the right.
01:06
So we will start from the left and find the longest parent chain.
01:12
When you have confusing molecules like this, always start the same way.
01:17
Look for the longest chain.
01:20
The others are substituents.
01:23
There are multiple ways to make a 5 -carbon chain with this molecule, but i have just chosen the way that makes most sense to me.
01:32
You can choose another way.
01:34
You could start with the side or move from one chain to the other...